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Question: If A. M. between p<sup>th</sup> and q<sup>th</sup> terms of an A.P. be equal to the A.M. between r<s...

If A. M. between pth and qth terms of an A.P. be equal to the A.M. between rth and sth terms of the A.P. then p + q is equal to –

A

r + s

B

rsr+s\frac{r - s}{r + s}

C

r+srs\frac{r + s}{r - s}

D

r + s + 1

Answer

r + s

Explanation

Solution

If 'a' be first term and 'd' be common difference of the given A.P.

A.M. between ap and aq = A.M. between ar and as

̃ 12\frac{1}{2} (ap + aq) = 12\frac{1}{2} (ar + as)

̃ (p + q – 2) d = (r + s – 2) d

̃ p + q = r + s