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Question: If a logarithm function is given as \(\dfrac{{\log 225}}{{\log 15}} = \log x\), then what is the val...

If a logarithm function is given as log225log15=logx\dfrac{{\log 225}}{{\log 15}} = \log x, then what is the value of x.
A. 400 B. 300 C. 200 D. 100  {\text{A}}{\text{. 400}} \\\ {\text{B}}{\text{. 300}} \\\ {\text{C}}{\text{. 200}} \\\ {\text{D}}{\text{. 100}} \\\

Explanation

Solution

Hint- Here, we will be using the basic formula of the logarithm function which is log(ab)=b(loga)\log \left( {{a^b}} \right) = b\left( {\log a} \right) along with the condition that if loga=b\log a = b then in order to get the value of x.

Complete step-by-step answer:
Given, log225log15=logx (1)\dfrac{{\log 225}}{{\log 15}} = \log x{\text{ }} \to {\text{(1)}}
Since a=(10)ba = {\left( {10} \right)^b}, the square of number 15 is equal to 225 i.e., 225=(15)2225 = {\left( {15} \right)^2}
Now, equation (1) becomes
log[(15)2]log15=logx (2)\dfrac{{\log \left[ {{{\left( {15} \right)}^2}} \right]}}{{\log 15}} = \log x{\text{ }} \to {\text{(2)}}
As we know that log(ab)=b(loga)\log \left( {{a^b}} \right) = b\left( {\log a} \right)
Using the above mentioned formula, equation (2) becomes
2log15log15=logx 2=logx logx=2 (3)  \dfrac{{2\log 15}}{{\log 15}} = \log x \\\ \Rightarrow 2 = \log x \\\ \Rightarrow \log x = 2{\text{ }} \to {\text{(3)}} \\\
Also we know that if loga=b\log a = b, then a=(10)ba = {\left( {10} \right)^b}
Using the above formula, equation (3) becomes
x=(10)2=100\Rightarrow x = {\left( {10} \right)^2} = 100
So, the required value of x is 100.
Hence, option D is correct.

Note- In this particular problem, we need to make sure that the given equation consists of the log function not ln function because both of these functions are different. For log function, the condition is that if loga=b\log a = b then a=(10)ba = {\left( {10} \right)^b} and for ln function, the condition is that if lna=b\ln a = b then a=eba = {e^b}.