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Question: If \[A = \left\\{ {x,y,z} \right\\}\] then the relation \[R = \left\\{ {\left( {x,x} \right),\left( ...

If A = \left\\{ {x,y,z} \right\\} then the relation R = \left\\{ {\left( {x,x} \right),\left( {y,y} \right),\left( {z,x} \right),\left( {z,y} \right)} \right\\} is
(A) Symmetric
(B) Transitive
(C) None of these
(D) Both A and B

Explanation

Solution

In order to find the given relation is reflexive, symmetric, or transitive, we first need to understand the definition of the reflexivity, symmetry and transitivity holds for a set. The relation is reflexive if (x,x)\left( {x,x} \right) belongs to the relation for all xx belongs to the set. The relation is symmetric if (x,y)\left( {x,y} \right) belongs to the relation implies that (y,z)\left( {y,z} \right) belongs to the same relation. And the relation is transitive if (x,y)&(y,z)\left( {x,y} \right)\& \left( {y,z} \right) belongs to the relation implies that (x,z)\left( {x,z} \right) belongs to the same relation.

Complete step by step solution:
The relation R in A is said to be reflexive, if (a,a)R for aA\left( {a,a} \right) \in R {\text{ for }} a \in A.
The relation R in A is said to be symmetric, if (a,b)R(b,a)R for a,bA\left( {a,b} \right) \in R \Rightarrow \left( {b,a} \right) \in R {\text{ for }} a, b \in A.
The relation R is said to be transitive if (x,y)R and (y,z)R(x,z)R for x,y,zA\left( {x,y} \right) \in R {\text{ and }} \left( {y,z} \right) \in R \Rightarrow \left( {x,z} \right) \in R {\text{ for }}x, y, z \in A.
As the given set A contains three elements, given as A = \left\\{ {x,y,z} \right\\} and the relation RR does not contain (z,z)\left( {z,z} \right) and zAz \in A, so the relation RR is not reflexive.
As (z,x)\left( {z,x} \right) belongs to the given relation RR and (x,z)\left( {x,z} \right) does not belong to the given relation RR. So by using the definition of symmetry.
So, it can be concluded that the given relation is not symmetric.
As (z,x)&(x,x)\left( {z,x} \right) \& \left( {x,x} \right) both belong to the given relation RR and (z,x)\left( {z,x} \right) also belong to the given relationRR and (z,y)&(y,y)\left( {z,y} \right) \& \left( {y,y} \right) both belong to the given relation RR and (z,y)\left( {z,y} \right)also belong to the relation RR.
From the above argument it can be concluded that, if (x,y)&(y,z)\left( {x,y} \right)\& \left( {y,z} \right) are belong to RR implies that (x,z)\left( {x,z} \right) belongs to the relation RR, then the relation is transitive.
Therefore, the given relation is transitive.

Hence, the correct option is B.

Note:
A relation is a relationship between sets of values or it is a subset of the Cartesian product. A function is a relation in which there is only one output for each input and a relation is denoted by RR and a function is denoted by FF.