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Question: If \[A = \left\\{ {0,2,4} \right\\}\] find \[A \cap \phi \] and \[A \cap A\]...

If A = \left\\{ {0,2,4} \right\\} find AϕA \cap \phi and AAA \cap A

Explanation

Solution

First, we understand the definition of the intersection of two sets. Now use the properties of intersection. Then give set AA to the intersection with an empty set. Then set AA to the intersection with itself. Finally, we get an answer.

Complete step-by-step answer:
The given set AA is nonempty. Set A = \left\\{ {0,2,4} \right\\}
First, we understand the intersection meaning AA and BB are sets. The common elements or objects of the two sets form the set. That is called AA intersection BB
A \cap B = \left\\{ {x:x \in A\,and\,x \in B} \right\\}
This is the definition of the intersection of two sets.
Now first we find AϕA \cap \phi
Set AA is \left\\{ {0,2,4} \right\\}. ϕ\phi means an empty set or null set. The set has no elements.
So that \phi = \left\\{ {} \right\\}
Now we find the intersection of AA an empty set.
A \cap \phi = \left\\{ {} \right\\}
Because the common element of both sets is none. So that answer of AA intersection empty set is a null set.
Next, we find AAA \cap A value,
We know that AA value is \left\\{ {0,2,4} \right\\}
Set AA is the intersection to itself. That means A \cap A = \left\\{ {0,2,4} \right\\}
Because the common element of both sets is whole elements. It means the intersection value AA and AA is AA.
So that,

A \cap A = \left\\{ {0,2,4} \right\\} \\\ = A \\\

The intersection of the empty set to non-empty is always an empty set. And the intersection of a set with itself is always getting the same set. These are important properties of the intersection of two sets.
Finally, we get the answers
A \cap \phi = \left\\{ {} \right\\},\,A \cap A = A

Note: First given a question to understand the definition of intersection or union of two sets. The intersection of the empty set to non-empty is always an empty set. And the intersection of a set with itself is always getting the same set. These properties are used carefully. Don't confuse intersection and union properties. Because union property is changeable.