Question
Question: If A is a square matrix such that, \[AadjA = diag\left( {k.k.k} \right)\], then \[\left| {adjA} \rig...
If A is a square matrix such that, AadjA=diag(k.k.k), then ∣adjA∣=
A. k
B. k2
C. k3
D. k4
Solution
Let A=[aij] be a square matrix. Then the transpose of a matrix of the cofactors of A is called adjoint of A and is denoted by adj(A) . So, Adjoint is the transpose of a matrix whose (i,j) entry is the aij cofactor.
- Any matrix of order m×nis said to be a square matrix when m=n, that is, the number of rows in the matrix is equal to the number of columns.
- A diagonal matrix is the matrix that has non zero diagonal elements and other elements as 0 and is represented as diag(a1,…,an).
- The determinant of a diagonal matrix is the product of all the diagonal elements.
- A(adjA)=(adjA)A=∣A∣In , where nis the order of matrix and In represents the identity matrix of order n×n
Complete step by step solution:
Given, AadjA=diag(k.k.k)
From the property of adjoint of a matrix A(adjA)=∣A∣In. Also AadjA=diag(k.k.k).
Therefore, ∣A∣In=diag(k.k.k).
From the property of diagonal of diagonal matrix ∣diag(k.k.k)∣=k3.
And, determinant of ∣A∣Inis equal to ∣A∣n.
It can be observed that the order of matrices is 3, that is n=3therefore determinant of ∣A∣In is ∣A∣3.
This implies that ∣A∣3=k3⇒∣A∣=k.
Substitute k for ∣A∣ and 3 for n into the formula for determinant of adjoint of a matrix, that is ∣adjA∣=∣A∣n−1 and solve.