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Question: If \(A\) is a square matrix of order \(3\) and \(\left| A \right| = 4\), find the value of \(\left| ...

If AA is a square matrix of order 33 and A=4\left| A \right| = 4, find the value of 2A\left| {2A} \right|.

Explanation

Solution

We are given the order of the matrix and determinant of the same matrix. If a row or column is multiplied by a number kk, the determinant is also multiplied by the same number. Since the order is three, there are three rows and columns. Using this we can find the determinant of 2A2A.

Useful formula:
The determinant of the matrix kAkA, kA=knA\left| {kA} \right| = {k^n}\left| A \right|, where nn is the order of the matrix.

Complete step by step solution:
Given that AA is a square matrix of order 33.
A square matrix is a matrix with the same number of rows and columns. The order of the square matrix is the number of its rows (or columns).
Also determinant of AA, A=4\left| A \right| = 4
We have to find the determinant of the matrix 2A2A.
If a row or column is multiplied by a number kk, the determinant is also multiplied by the same number.
When we consider kAkA, every row of the matrix is multiplied by the number kk.
So the determinant of the matrix kAkA, kA=knA\left| {kA} \right| = {k^n}\left| A \right|, where nn is the order of the matrix.
Since the order of the matrix is given as 33, we have
2A=23A\left| {2A} \right| = {2^3}\left| A \right|
Substituting the determinant of the matrix AA we get,
2A=23×4\left| {2A} \right| = {2^3} \times 4
Simplifying we get,
2A=8×4=32\left| {2A} \right| = 8 \times 4 = 32

Therefore the answer is 3232.

Note:
In the question, it is said that the matrix is a square matrix. The determinant is defined only for square matrices. For a square matrix, every scalar multiple will also be a square matrix. So the determinant is defined for 2A2A.