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Question: If \(A\) is \(3 \times 4\) matrix and \(b\) is the matrix such that \(A'B, BA'\) are both defined th...

If AA is 3×43 \times 4 matrix and bb is the matrix such that AB,BAA'B, BA' are both defined then BB matrix is of type
A. 3×43 \times 4
B. 3×33 \times 3
C. 4×44 \times 4
D. 4×34 \times 3

Explanation

Solution

Let us assume that BB is m×nm \times n matrix and AA' and BB' are defined as the transpose of A,BA,B respectively. So if AA is 3×43 \times 4 matrix then its transpose will be 4×34 \times 3 matrix. ABA'B is defined so the number of columns of AA' must be equal to the number of rows of BB and similarly for BABA'. So we will find m×nm \times n and we can get our answer.

Complete step by step solution:
Now firstly we need to find the meaning of the transpose matrix. Let we have the matrix AA of order i×ji \times j then for AA' to be the transpose of AA it will becomej×ij \times i.
For example: WE have the matrix A as \left[ { \begin{array}{*{20}{c}} a&b;&c; \end{array} \\\ \begin{array}{*{20}{c}} d&e;&f; \end{array} } \right] of order 2×32 \times 3
Then AA' is defined as the transpose of A which is A' = \left[ {\begin{array}{*{20}{c}} a \\\ b \\\ c \end{array}{\text{ }}\begin{array}{*{20}{c}} d \\\ e \\\ f \end{array}} \right]
Which is 3×23 \times 2 matrix
For the multiplication of the matrices A and B which means to get ABAB number of columns in AA must be equal to the number of rows in BB
That means if A is i×ji \times j then for AB to be defined B must be j×kj \times k matrix and here jj is the column of A and row of B.
And we are given that matrix AAis 3×43 \times 4 matrix and transpose of AA which is A=A' = 4×34 \times 3
Also we assumed that BB be m×nm \times n matrix then the transpose of BB which is B=n×mB' = n \times m
Now for ABA'B to be defined number of columns of AA' must be equal to number of rows of BB
So number of columns in AA' is 33
Number of rows in BB is m
So m=3m = 3
For BABA' to be defined the number of columns of BB must be equal to the number of rows of AA'
So n=4n = 4
Now we assumed that BB is m×nm \times n matrix

Therefore 3×43 \times 4 is the answer.

Note:
If matrix AA is given m×nm \times n and matrix BB is given by P×QP \times Q then for AB to be defined
n=Pn = P and for BA to be defined m=Qm = Q
So for both AB and BA to be defined n=P,Q=mn = P, Q = m
Therefore both must have the same number of rows and columns.