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Question: If \(a = i + j\) and \(b = 2i - k\) are two vectors, then the point of intersection of two lines \(r...

If a=i+ja = i + j and b=2ikb = 2i - k are two vectors, then the point of intersection of two lines r×a=b×ar \times a = b \times a and r×b=a×br \times b = a \times b is

A

i + jk

B

ij + k

C

3i + jk

D

3ij + k

Answer

3i + jk

Explanation

Solution

Let r=xi+yj+zk\mathbf{r} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k}, then r×a=b×a\mathbf{r} \times \mathbf{a} = \mathbf{b} \times \mathbf{a}

(rb)×a=0(\mathbf{r} - \mathbf{b}) \times \mathbf{a} = 0 ijkx2yz+1110=0\Rightarrow \left| \begin{aligned} & ijk \\ & x - 2yz + 1 \\ & 110 \end{aligned} \right| = 0,

z=1,xy=2\therefore z = - 1,x - y = 2

Now r×b=a×b\mathbf{r} \times \mathbf{b} = \mathbf{a} \times \mathbf{b}(ra)×b=0(\mathbf{r} - \mathbf{a}) \times \mathbf{b} = 0

y=1,x+2z=1\therefore y = 1,x + 2z = 1 x=3,y=1,z=1\Rightarrow x = 3,y = 1,z = - 1

r=3i+jk\mathbf{r} = 3\mathbf{i} + \mathbf{j} - \mathbf{k}.