Question

if A=$\frac{1}{5! 6! 7!}\begin{bmatrix} 5! & 6! & 7!\\\ 6! & 7! & 8! \\\ 7! & 8! & 9! \end{bmatrix}$, then |adj(adj(2A))| is equal t

• A. $2^{20}$
• B. $2^{16}$
• C. $2^{12}$
• D. $2^{8}$

Answer 1

Answer: (B)

$2^{16}$

Answer 2

The correct option is(B): $2^{16}$