Question
Question: If a dip circle is placed in a vertical plane at an angle of 30° to the magnetic meridian, the dip n...
If a dip circle is placed in a vertical plane at an angle of 30° to the magnetic meridian, the dip needle makes an angle of 45° with the horizontal. The real dip at that place is
& \text{A}\text{. ta}{{\text{n}}^{-1}}\left( \dfrac{\sqrt{3}}{2} \right) \\\ & \text{B}\text{. ta}{{\text{n}}^{-1}}\left( \sqrt{3} \right) \\\ & \text{C}\text{. ta}{{\text{n}}^{-1}}\left( \dfrac{\sqrt{3}}{\sqrt{2}} \right) \\\ & \text{D}\text{. ta}{{\text{n}}^{-1}}\left( \dfrac{2}{\sqrt{3}} \right) \\\ \end{aligned}$$Solution
To find the angle of dip we have to find out the vertical component and horizontal component of earth’s magnetic field in the magnetic meridian.
Formula used: Angle of dip = tanθ=hv
Complete step by step solution:
Let us assume the vertical component and horizontal component of earth’s magnetic field at magnetic meridian as v and h respectively.
Angle of dip which is defined as the angle made by the earth’s magnetic field line with the horizontal is given by,
tanθ=hv……………. (i) [where, is the dip angle]
We should consider the angle of dip to be positive when the magnetic field lines point downwards and negative when the magnetic field lines point upwards.
For 30° to the meridian and 40° to the horizontal,