Question

If a die is thrown twice, then the probability of throwing a sum of seven is

• A. 1/6
• B. 1/3
• C. 5/6
• D. 2/3

Answer 1

Answer: (A)

1/6

Answer 2

n(S) = 6² = 36.

Let E be the event of throwing sum 7

E = {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)}.

N(5) = 6.

Probability = $\frac { 6 } { 36 } = \frac { 1 } { 6 }$ .