Question

If a dice is thrown twice, then the probability of getting 1 in the first throw only is

• A. $\frac { 1 } { 36 }$
• B. $\frac { 3 } { 36 }$
• C. $\frac { 5 } { 36 }$
• D. $\frac { 1 } { 6 }$

Answer 1

Answer: (C)

$\frac { 5 } { 36 }$

Answer 2

Probability of getting 1 in first throw $= \frac { 1 } { 6 }$

Probability of not getting 1 in second throws $= \frac { 5 } { 6 }$

Both are independent events, so the required probability $= \frac { 1 } { 6 } \times \frac { 5 } { 6 } = \frac { 5 } { 36 }$.