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Question

Mathematics Question on Binomial theorem

If AA denotes the sum of all the coefficients in the expansion of (13x+10x2)n(1 - 3x + 10x^2)^n and BB denotes the sum of all the coefficients in the expansion of (1+x2)n(1 + x^2)^n, then:

A

A=B3A = B^3

B

3A=B3A = B

C

B=A3B = A^3

D

A=3BA = 3B

Answer

A=B3A = B^3

Explanation

Solution

To find the sums AA and BB, we calculate the sum of all coefficients by setting x=1x = 1 in each expansion.

Step 1. Calculate AA

Substitute x=1x = 1 in (13x+10x2)n(1 - 3x + 10x^2)^n:A=(131+1012)n=(13+10)n=8nA = (1 - 3 \cdot 1 + 10 \cdot 1^2)^n = (1 - 3 + 10)^n = 8^nTherefore, A=8nA = 8^n.

Step 2. Calculate BB

Substitute x=1x = 1 in (1+x2)n(1 + x^2)^n:B=(1+12)n=2nB = (1 + 1^2)^n = 2^nThus, B=2nB = 2^n.

Step 3. Find the Relationship Between AA and BB

Since A=8nA = 8^n and B=2nB = 2^n, we can write:A=(2n)3=B3A = (2^n)^3 = B^3Therefore, A=B3A = B^3.