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Question: If a cylinder of diameter 1.0 cm at 30°C is to be solid into a hole of diameter 0.9997 cm in a steel...

If a cylinder of diameter 1.0 cm at 30°C is to be solid into a hole of diameter 0.9997 cm in a steel plate at the same temperature, then minimum required rise in the temperature of the plate is : (Coefficient of linear expansion of steel =12×106/C= 12 \times 10^{- 6}/{^\circ}C)

A

25°C

B

35°C

C

45°C

D

55°C

Answer

25°C

Explanation

Solution

α=ΔLL0Δθ=(10.9997)0.9997×12×106=25C\alpha = \frac{\Delta L}{L_{0}\Delta\theta} = \frac{(1 - 0.9997)}{0.9997 \times 12 \times 10^{- 6}} = 25{^\circ}C