Question

If a cyclist moving with a speed of $4.9\mspace{6mu} m/s$ on a level road can take a sharp circular turn of radius $4m$, then coefficient of friction between the cycle tyres and road is

• A. 0.41
• B. 0.51
• C. 0.71
• D. 0.61

Answer 1

Answer: (D)

0.61

Answer 2

$v = 4.9m/s,r = 4m$ and $g = 9.8m/s^{2}$ (given)

$\mu = \frac{v^{2}}{rg} = \frac{4.9 \times 4.9}{4 \times 9.8} = 0.61$