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Question

Physics Question on Motion in a plane

If a cycle wheel of radius 4 m4\,m completes one revolution in two seconds. Then acceleration of the cycle will be

A

π2m/s2\pi ^{2}m/s^{2}

B

2π2m/s2 2\pi ^{2}m/s^{2}

C

4π2m/s2 4\pi ^{2}m/s^{2}

D

8π  m/s2 8\pi \,\,m/s^{2}

Answer

4π2m/s2 4\pi ^{2}m/s^{2}

Explanation

Solution

Here : Frequency of revolution t=12rev/sec⁡t=\frac{1}{2} rev / \sec Radius of wheel of cycle r=4 mr=4\, m The acceleration of the wheel is given by =rω2=r×(2πf)2=r \omega^{2}=r \times(2 \pi f)^{2} =4×(2×π×12)2=4 \times\left(2 \times \pi \times \frac{1}{2}\right)^{2} =4π2m/s2=4 \pi^{2} m / s ^{2}