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Question

Physics Question on Moving charges and magnetism

If a current II is flowing in a loop of radius rr as shown in adjoining figure, then the magnetic field induction at the centre OO will be

A

Zero

B

μ0Iθ4πr\frac{\mu_{0}I \theta}{4\pi r}

C

μ0Isinθ4πr\frac{\mu_{0}I sin \theta}{4\pi r}

D

2μ0Isinθ4πr2\frac{2\mu_{0}I sin \theta}{4\pi r^{2}}

Answer

μ0Iθ4πr\frac{\mu_{0}I \theta}{4\pi r}

Explanation

Solution

Magnetic field B = μ04π2πIr\frac{\mu_{0}}{4\pi}\frac{2\pi I}{r}
Here, 2π=θ2\pi=\theta
B=μ04πθIr\therefore B=\frac{\mu_{0}}{4\pi}\frac{\theta I}{r}