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Question: If a current I given by \(I _ { 0 } \sin \left( \omega t - \frac { \pi } { 2 } \right)\) flows in an...

If a current I given by I0sin⁡(ωt−π2)I _ { 0 } \sin \left( \omega t - \frac { \pi } { 2 } \right) flows in an ac circuit across which an ac potential of E=E0sin⁡ωtE = E _ { 0 } \sin \omega t has been applied, then the power consumption P in the circuit will be

A

P=E0I02P = \frac { E _ { 0 } I _ { 0 } } { \sqrt { 2 } }

B

P=2E0I0P = \sqrt { 2 } E _ { 0 } I _ { 0 }

C

P=E0I02P = \frac { E _ { 0 } I _ { 0 } } { 2 }

D

P = 0

Answer

P = 0

Explanation

Solution

Phase angle ϕ=90∘\phi = 90 ^ { \circ } , so power P=Vicos⁡ϕ=0P = V i \cos \phi = 0