Question
Question: If a copper rod (free to move and rotate) is brought in a region of a non – uniform magnetic field, ...
If a copper rod (free to move and rotate) is brought in a region of a non – uniform magnetic field, then it will align itself

A
Along the direction of the magnetic field, at a location where the magnetic field is strongest
B
Along the direction of the magnetic field, at a location where the magnetic field is weakest
C
Perpendicular to the direction of the magnetic field, at a location where the magnetic field is strongest
D
Perpendicular to the direction of the magnetic field, at a location where the magnetic field is weakest
Answer
Perpendicular to the direction of the magnetic field, at a location where the magnetic field is weakest
Explanation
Solution
Key concepts
- Copper is diamagnetic, so it develops an induced magnetic moment opposite to the applied field.
- The magnetic potential energy for a magnetic moment $\vec m$ in field $\vec B$ is
$$ U = -\vec m \cdot \vec B. $$ - For a diamagnet, $\vec m$ is antiparallel to $\vec B$, so to minimize energy the rod seeks regions of weaker field.
- Torque $\tau = \vec m \times \vec B$ aligns the rod so that $\vec m\perp\vec B$, making $m\cdot B=0$.
Therefore, the copper rod aligns perpendicular to the field in the weakest region.