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Question

Physics Question on mechanical properties of solids

If a conical wire is stretched by two forces F applied, parallel to its length and In opposite direction. NoramI to end faces. The length of wire is L and its end radius are r1r_1 and r2r_2 Find out the extention produced (Given: Y=Young's modulus of wire)

A

FLπr12Y\frac{FL}{\pi r^2_1 Y}

B

FLπr1Y\frac{FL}{\pi r_1 Y}

C

FLπr1r2Y\frac{FL}{\pi r_1r_2 Y}

D

FLπr12\frac{FL}{\pi r^2_1 }

Answer

FLπr1r2Y\frac{FL}{\pi r_1r_2 Y}

Explanation

Solution

ΔL=FLγA=FLγA1A2=FLγπr12r22\Delta L = \frac{FL}{\gamma A} = \frac{FL}{\gamma \sqrt{A_1 A_2}} = \frac{FL}{\gamma \sqrt{\pi r_1^2 r_2^2}} ΔL=FLγπr1r2\Delta L = \frac{FL}{\gamma \, \pi \, r_1 r_2}