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Question: If a circle whose centre is (1, – 3) touches the line 3x – 4y – 5 = 0, then the radius of the circl...

If a circle whose centre is (1, – 3) touches the line

3x – 4y – 5 = 0, then the radius of the circle is –

A

2

B

4

C

52\frac{5}{2}

D

72\frac{7}{2}

Answer

2

Explanation

Solution

Radius = perpendicular distance from(1, –3) to

3x – 4y – 5 = 0 i.e. ∣3+12–5/9+16∣\left| 3 + 12–5/\sqrt{9 + 16} \right| = 2