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Question: If a circle cuts a rectangular hyperbola \(xy = c^{2}\) in A, B, C, D and the parameters of these fo...

If a circle cuts a rectangular hyperbola xy=c2xy = c^{2} in A, B, C, D and the parameters of these four points be t1,t2,t3t_{1},t_{2},t_{3}and t4t_{4} respectively. Then

A

t1t2=t3t4t_{1}t_{2} = t_{3}t_{4}

B

t1t2t3t4=1t_{1}t_{2}t_{3}t_{4} = 1

C

t1=t2t_{1} = t_{2}

D

t3=t4t_{3} = t_{4}

Answer

t1t2t3t4=1t_{1}t_{2}t_{3}t_{4} = 1

Explanation

Solution

Let the equation of circle be x2+y2=a2x^{2} + y^{2} = a^{2} ......(i)

Parametric equation of rectangular hyperbola is x=ct,y=ctx = ct,y = \frac{c}{t}

Put the values of x and y in equation (i) we get c2t2+c2t2=a2c^{2}t^{2} + \frac{c^{2}}{t^{2}} = a^{2}c2t4a2t2+c2=0c^{2}t^{4} - a^{2}t^{2} + c^{2} = 0

Hence product of rootst1t2t3t4=c2c2=1t_{1}t_{2}t_{3}t_{4} = \frac{c^{2}}{c^{2}} = 1