Question

If a charged spherical conductor of radius 10 cm has potential V at a point distant 5 cm from its centre, then the potential at a point distant 15 cm from the centre will be:

• A. $\text{3V}$
• B. $\text{3/2V}$
• C. $\text{2/3V}$
• D. $\text{1/3V}$

Answer 1

Answer: (C)

$\text{2/3V}$

Answer 2

We know that the potential inside and on the surface of a spherical conductor is same so $V={{V}_{surface}}=\frac{q}{10}\text{stat}\,\text{volt}$ ${{V}_{out}}=\frac{q}{15}\text{stat}\,\text{volt}$ $\frac{{{V}_{out}}}{V}=\frac{2}{3}$ so ${{V}_{out}}=\frac{2}{3}V$