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Question: If a change of100 \(\mu A\) in rthe base current of an n – p – n transistor causes as change of 10 m...

If a change of100 μA\mu A in rthe base current of an n – p – n transistor causes as change of 10 mA in its collector current its ac current gain is.

A

50

B

100

C

200

D

150

Answer

100

Explanation

Solution

here, ΔIB=100μA=100×10−6A\Delta I_{B} = 100\mu A = 100 \times 10^{- 6}A

ΔIC=10mA=10×10−3A\Delta I_{C} = 10mA = 10 \times 10^{- 3}A

∴\thereforeAc current gain

βac=ΔICΔIB=10×10−3100×10−6=100\beta_{ac} = \frac{\Delta I_{C}}{\Delta I_{B}} = \frac{10 \times 10^{- 3}}{100 \times 10^{- 6}} = 100