Question

If a carnot engine is working between steam point and ice point, then its efficiency will be

• A. 24.9 %
• B. 25.7%
• C. 26.8%
• D. 28.8%

Answer 1

Answer: (C)

26.8%

Answer 2

Here, ice point

$T_{2} = 0ºC = 0 + 273 = 273k$

And steam point

$T_{1} = 100ºC = 100 + 273 = 373k$

Efficiency of the carnot engine

$\eta = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{273}{373} = \frac{100}{373} = \frac{100}{373} \times 100\% = 26.8\%$