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Question: If a car covers 2/5<sup>th</sup> of the total distance with v<sub>1</sub> speed and 3/5<sup>th</sup>...

If a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then average speed is

A

12v1v2\frac { 1 } { 2 } \sqrt { v _ { 1 } v _ { 2 } }

B

v1+v22\frac { v _ { 1 } + v _ { 2 } } { 2 }

C

2v1v2v1+v2\frac { 2 v _ { 1 } v _ { 2 } } { v _ { 1 } + v _ { 2 } }

D

5v1v23v1+2v2\frac { 5 v _ { 1 } v _ { 2 } } { 3 v _ { 1 } + 2 v _ { 2 } }

Answer

5v1v23v1+2v2\frac { 5 v _ { 1 } v _ { 2 } } { 3 v _ { 1 } + 2 v _ { 2 } }

Explanation

Solution

Average speed = Total distance travelled  Total time taken \frac { \text { Total distance travelled } } { \text { Total time taken } } =xt1+t2= \frac { x } { t _ { 1 } + t _ { 2 } }

= =5v1v22v2+3v1= \frac { 5 v _ { 1 } v _ { 2 } } { 2 v _ { 2 } + 3 v _ { 1 } }