Question

If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block is

• A. 8300 N
• B. 417 N
• C. 830 N
• D. Zero

Answer 1

Answer: (B)

417 N

Answer 2

$u = 100\mspace{6mu} m/s,\mspace{6mu} v = 0,\mspace{6mu} s = 0.06\mspace{6mu} m$

Retardation $= a = \frac{u^{2}}{2s} = \frac{(100)^{2}}{2 \times 0.06} = \frac{1 \times 10^{6}}{12}$

$\therefore$ Force $= ma = \frac{5 \times 10^{- 3} \times 1 \times 10^{6}}{12} = \frac{5000}{12} = 417\mspace{6mu} N$