Question: If a block moving up at $\theta = 30^{o}$ with a velocity 5 m/s, stops after 0.5 sec, then what is...

Question

If a block moving up at $\theta = 30^{o}$ with a velocity 5 m/s, stops after 0.5 sec, then what is μ

Answer 1

From $v = u - at$ ⇒ 0 $= u - at$ $\therefore t = \frac{u}{a}$

for upward motion on an inclined plane

$a = g(\sin\theta + \mu\cos\theta)$ $\therefore t = \frac{u}{g(\sin\theta + \mu\cos\theta)}$

Substituting the value of $\theta = 30^{o},t = 0.5\sec$ and

$u = 5m/s$ , we get $\mu = 0.6$

Question: If a block moving up at \(\theta = 30^{o}\) with a velocity 5 m/s, stops after 0.5 sec, then what is...