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Question: If A = \(\begin{bmatrix} 4 & x + 2 \\ 2x–3 & x + 1 \end{bmatrix}\) is symmetric, then x =...

If A = [4x+22x–3x+1]\begin{bmatrix} 4 & x + 2 \\ 2x–3 & x + 1 \end{bmatrix} is symmetric, then x =

A

3

B

5

C

2

D

4

Answer

5

Explanation

Solution

A' = A

\ [42x–3x+2x+1]\begin{bmatrix} 4 & 2x–3 \\ x + 2 & x + 1 \end{bmatrix}= [4x+22x–3x+1]\begin{bmatrix} 4 & x + 2 \\ 2x–3 & x + 1 \end{bmatrix}

\ x + 2 = 2x –3 Ž x = 5