Question
Question: If A = \(\begin{bmatrix} –1 & –2 & –2 \\ 2 & 1 & –2 \\ 2 & –2 & 1 \end{bmatrix}\), then adj A =...
If A = –122–21–2–2–21, then adj A =
A
A
B
AT
C
3A
D
3AT
Answer
3AT
Explanation
Solution
Adj A = $\begin{bmatrix}
- (–3) & –6 & + (–6) \ –(–6) & + 3 & –6 \
- 6 & –6 & + 3 \end{bmatrix}$
= 3 –1–2–221–22–21′
= 3. AT