Question
Question: If A = \(\begin{bmatrix} 0 & 1 & 2 \\ 1 & 2 & 3 \\ 3 & a & 1 \end{bmatrix}\) and A<sup>–1</sup> = \(...
If A = 01312a231 and A–1 = 1/2–45/2–1/23–3/21/2c1/2, then the value of a and c is equal to –
A
–1, 1
B
1, 2
C
1, – 1
D
1, 1
Answer
1, – 1
Explanation
Solution
AA–1 = I
01312a231 1/2–45/2–1/23–3/21/2c–1/2↓↓ = 100010001
Comparing (a31)
Ž 23 – 4a + 25 = 0
4 – 4a = 0
a = 1 \end{matrix}$$ Comparing (a<sub>13</sub>) 0 + C + 1 0 C = – 1