Question

If $A = \begin{bmatrix} -\frac{1}{\sqrt{2}} & \frac{1}{\sqrt{2}} & 0 \\\ -\frac{1}{\sqrt{2}} & -\frac{1}{\sqrt{2}} & 0 \\\ 0 & 0 & 1 \end{bmatrix}$, then $A^{-1}$ is:

• A. $A$
• B. $A^T$
• C. $A^2$
• D. $A^3$

Answer 1

Answer: (B)

$A^T$

Answer 2

The correct option is (B):$A^T$