Question
Mathematics Question on Determinants
If A=1\2\5114−2−3−9,find IAI.
Answer
Let A=1\2\5114−2−3−9
By expanding along the first row, we have:
IAI=11\4−3−9−12\5−3−9−22\5−14
=1(-9+12)-1(-18+15)-2(8-5)
=3+3-6
=6-6=0
If A=1\2\5114−2−3−9,find IAI.
Let A=1\2\5114−2−3−9
By expanding along the first row, we have:
IAI=11\4−3−9−12\5−3−9−22\5−14
=1(-9+12)-1(-18+15)-2(8-5)
=3+3-6
=6-6=0