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Question

Mathematics Question on Determinants

If A=[110 215 121]A=\begin{bmatrix}1&1&0\\\ 2&1&5\\\ 1&2&1\end{bmatrix}, then a11A21+a12A22+a13A23a_{11}A_{21} +a_{12}A_{22}+a_{13}A_{23} is equal to

A

11

B

00

C

1-1

D

22

Answer

00

Explanation

Solution

Given, A=[110 215 121]A=\begin{bmatrix}1&1&0\\\ 2&1&5\\\ 1&2&1\end{bmatrix}
We know that, the sum of the product of element other than the corresponding cofactor
is zero
a11A21+a12A22+a13A23=0\therefore a_{11}A_{21}+a_{12}A_{22}+a_{13}A_{23}=0