Question

If A be the A.M. and G be the G.M. between two numbers. Show that the numbers are given by $A \pm \sqrt {{A^2} - {G^2}}$

Answer 1

We know that A.M. is arithmetic mean, and G.M. is geometric mean, and A.M and G.M. for two numbers say ‘a’ and ‘b’ will be $\dfrac{{a + b}}{2}$ and $\sqrt[{}]{{ab}}$ respectively. We will make a quadratic equation using it, and the roots of the equation gives the value of the numbers which we have to prove.

Complete step-by-step solution:
Given, A and G are A.M and G.M between two numbers. Let the two numbers be ‘a’ and ‘b’, we know that A.M between two numbers is the average of two numbers and G.M between two numbers is the square root of the product of the numbers.
Then, $A = \dfrac{{a + b}}{2}$ and $G = \sqrt {ab}$
Simplifying them, we get:
$\Rightarrow a + b = 2A\,\,\,\,\,---------- equation\,1$
and,
$\Rightarrow ab = {G^2}\,\,\,\,\, -------- equation\,2$

\Rightarrow {\left( {a - b} \right)^2} = {\left( {2A} \right)^2} - 4{G^2} \\\ \Rightarrow {\left( {a - b} \right)^2} = 4\left( {{A^2} - {G^2}} \right) \\\ \Rightarrow \left( {a - b} \right) = \pm 2\sqrt {{A^2} - {G^2}} \,\,--- equation\,3$$ Taking equation 1 and equation 2 we get,

\Rightarrow a - b = 2\sqrt {{A^2} - {G^2}} \\
\Rightarrow a + b = 2A $Now adding both we get:$ \Rightarrow a = A + \sqrt {{A^2} - {G^2}} $$
Putting this value of ‘a’ in equation 1, we get:

\Rightarrow A + \sqrt {{A^2} - {G^2}} + b = 2A $$ Calculating the value of ‘b’, we get: $$ \Rightarrow b = A - \sqrt {{A^2} - {G^2}} $$ This equation can also we written as: $$ = A - \sqrt {\left( {A + G} \right)\left( {A - G} \right)} $$ **Hence, the numbers are $$A \pm \sqrt {{A^2} - {G^2}} $$** **Note:** We have to be careful while solving quadratic equation questions as there are chances of mistakes with signs while finding the roots. Sometimes the students try to use factorization methods to solve the quadratic equation, but in this type of questions, it is not recommended at all. Always try to use the quadratic formula for solving.