If A: B=C: D, then the value of (\frac{A^2+B^2}{C^2+D^2}) is... | Quantitative Ability and Data Interpretation | SolveeIt | Solveeit

Today, August 24

Question

If A: B=C: D, then the value of $\frac{A^2+B^2}{C^2+D^2}$ is

A

$\frac{1}{2}$

B

$\frac{A+ B}{C +D}$

C

$\frac{A- B}{C -D}$

D

$\frac{A\times B}{C \times D}$

Answer

$\frac{A\times B}{C \times D}$

Explanation

Solution

The Correct Option is (D): $\frac{A\times B}{C \times D}$