Question

If $a, b, c, d, e, f$ are in A.P., then $e - c$ is equal to :

• A. 2(c - a)
• B. 2(d - c)
• C. 2(f - d)
• D. (d - c)

Answer 1

Answer: (B)

2(d - c)

Answer 2

Let $x$ be the common difference of the A.P. $a , b , c , d , e , f$. As e is the 5 th term $\therefore e = a +(5-1) x \quad\left(\because a _{ n }= a +( n -1) d \right)$, where $a _n$ is the $nth$ term