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Question

Question: If *a*, *b*, *c*, *d*, *e*, *f* are A.M.’s between 2 and 12, then \(a + b + c + d + e + f\) is equal...

If a, b, c, d, e, f are A.M.’s between 2 and 12, then a+b+c+d+e+fa + b + c + d + e + f is equal to

A

14

B

42

C

84

D

None of these

Answer

42

Explanation

Solution

Since, a, b, c, d, e, f are six A.M.’s between 2 and 12

Therefore, a+b+c+d+e+f=62(a+f)=62(2+12)=42a + b + c + d + e + f = \frac{6}{2}(a + f) = \frac{6}{2}(2 + 12) = 42