Question

If a, b, c are the position vectors of the vertices A, B, C of the triangle ABC, then the centroid of $\Delta ABC$ is

• A. $\frac{\mathbf{a} + \mathbf{b} + \mathbf{c}}{3}$
• B. $\frac{1}{2}\left( \mathbf{a} + \frac{\mathbf{b} + \mathbf{c}}{2} \right)$
• C. $\mathbf{a} + \frac{\mathbf{b} + \mathbf{c}}{2}$
• D. $\frac{\mathbf{a} + \mathbf{b} + \mathbf{c}}{2}$

Answer 1

Answer: (A)

$\frac{\mathbf{a} + \mathbf{b} + \mathbf{c}}{3}$

Answer 2

It is obvious.