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Question

Mathematics Question on Trigonometric Equations

If A, B, C are the angles of ΔABC\Delta ABC then cotA.cotB+cotB.cotC+cotC.cotA=\cot \, A. \cot \, B + \cot \, B. \cot \, C + \cot \, C. \cot \, A =

A

0

B

1

C

2

D

-1

Answer

1

Explanation

Solution

Given, A+B+C=πA+B+C=\pi
A+B=πC\Rightarrow A+B=\pi-C
cot(A+B)=cot(πC)\Rightarrow \cot (A+B)=\cot (\pi-C)
cotAcotB1cotA+cotB=cotC\Rightarrow \frac{\cot A \cot B-1}{\cot A+\cot B}=-\cot C
cotAcotB1=cotAcotCcotBcotC\Rightarrow \cot A \cot B-1=-\cot A \cot C-\cot B \cot C
cotAcotB+cotBcotC+cotCcotA=1\Rightarrow \cot A \cot B+\cot B \cot C+\cot C \cot A=1