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Question: If a, b, c are in H.P., then the straight line \(\frac { \mathrm { x } } { \mathrm { a } } + \frac ...

If a, b, c are in H.P., then the straight line xa+yb+1c\frac { \mathrm { x } } { \mathrm { a } } + \frac { \mathrm { y } } { \mathrm { b } } + \frac { 1 } { \mathrm { c } } = 0 always passes through a fixed point and that point is

A

(–1, –2)

B

(–1, 2)

C

(1, –2)

D

(1,12)\left( 1 , \frac { 1 } { 2 } \right)

Answer

(1, –2)

Explanation

Solution

1a2b+1c=0\frac { 1 } { a } - \frac { 2 } { b } + \frac { 1 } { c } = 0

The line xa+yb+1c=0\frac { x } { a } + \frac { y } { b } + \frac { 1 } { c } = 0 passes through the pt

(1, –2)