Question
Question: If *a*, *b*, *c* are in A.P. and \|*a*\|, \|*b*\|, \|*c*\| \< 1, and \(x = 1 + a + a ^ { 2 } + \ldot...
If a, b, c are in A.P. and |a|, |b|, |c| < 1, and x=1+a+a2+…∞, y=1+b+b2+…∞ , z=1+c+c2+……∞
Then x, y, z shall be in
A
A.P.
B
G.P.
C
H.P.
D
None of these
Answer
H.P.
Explanation
Solution
x=1+a+a2+…∞=1−a1
z=1+c+c2+….∞=1−c1
Now, a, b, c are in A.P.
⇒ 1 – a, 1 – b, 1 – c are in A.P.
⇒ 1−a1,1−b1,1−c1 are in H.P.
Therefore x, y, z are in H.P.