Question
Question: If a,b,c are in A.P. and geometric means of \(ac\) and \(ab\) , \(ab\) and \(bc\) , \(ca\) and \(cb\...
If a,b,c are in A.P. and geometric means of ac and ab , ab and bc , ca and cb are d,e,f respectively then d2,e2,f2 are in:
(1) A.P.
(2) G.P.
(3) H.P.
(4) A.G.P.
Solution
Here in this question, we have been given the following information “a,b,c are in A.P. and geometric means of ac and ab , ab and bc , ca and cb are d,e,f respectively” and asked to find the name of the progression d2,e2,f2. Consecutive terms in A.P. have a common difference.
Complete step by step solution:
Now considering from the question we have been given that “a,b,c are in A.P. and geometric means of ac and ab , ab and bc , ca and cb are d,e,f respectively”.
From the basic concepts, we know that the consecutive terms in A.P. have a common difference.
Hence we can say that b−a=c−b⇒2b=a+c .
From the basic concepts, we know that the geometric mean of any two numbers p,q is given as pq .
Hence we can say that ab×ac=d, ab×bc=eand cb×ca=f .
Hence we can say that d2=a2(bc) , e2=b2(ac) and f2=c2(ab) .
Let us simplify it further then we will have
d2+f2=a2(bc)+c2(ab)⇒d2+f2=(abc)(a+c) .
Let us use b=2a+c then we will have ⇒d2+f2=(2ac)(a+c)2 .
Now let us use b=2a+c then we will have ⇒e2=(2a+c)2(ac).
Hence we can say that 2e2=d2+f2 .
Therefore we can conclude that if a,b,c are in A.P. and geometric means of ac and ab , ab and bc , ca and cb are d,e,f respectively then d2,e2,f2 are in A.P.
Hence we will mark the option “1” as correct.
Note: While answering questions of this type, we should be sure of the concepts that we are going to use in between the steps. Very few mistakes are possible in questions of this type. This is directly based on the concept of progressions without involving much calculation.