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Question: If a,b,c are in A.P. and geometric means of \(ac\) and \(ab\) , \(ab\) and \(bc\) , \(ca\) and \(cb\...

If a,b,c are in A.P. and geometric means of acac and abab , abab and bcbc , caca and cbcb are d,e,fd,e,f respectively then d2,e2,f2{{d}^{2}},{{e}^{2}},{{f}^{2}} are in:
(1) A.P.
(2) G.P.
(3) H.P.
(4) A.G.P.

Explanation

Solution

Here in this question, we have been given the following information “a,b,ca,b,c are in A.P. and geometric means of acac and abab , abab and bcbc , caca and cbcb are d,e,fd,e,f respectively” and asked to find the name of the progression d2,e2,f2{{d}^{2}},{{e}^{2}},{{f}^{2}}. Consecutive terms in A.P. have a common difference.

Complete step by step solution:
Now considering from the question we have been given that “a,b,ca,b,c are in A.P. and geometric means of acac and abab , abab and bcbc , caca and cbcb are d,e,fd,e,f respectively”.
From the basic concepts, we know that the consecutive terms in A.P. have a common difference.
Hence we can say that ba=cb2b=a+cb-a=c-b\Rightarrow 2b=a+c .
From the basic concepts, we know that the geometric mean of any two numbers p,qp,q is given as pq\sqrt{pq} .
Hence we can say that ab×ac=d\sqrt{ab\times ac}=d, ab×bc=e\sqrt{ab\times bc}=eand cb×ca=f\sqrt{cb\times ca}=f .
Hence we can say that d2=a2(bc){{d}^{2}}={{a}^{2}}\left( bc \right) , e2=b2(ac){{e}^{2}}={{b}^{2}}\left( ac \right) and f2=c2(ab){{f}^{2}}={{c}^{2}}\left( ab \right) .
Let us simplify it further then we will have
d2+f2=a2(bc)+c2(ab) d2+f2=(abc)(a+c) \begin{aligned} & {{d}^{2}}+{{f}^{2}}={{a}^{2}}\left( bc \right)+{{c}^{2}}\left( ab \right) \\\ & \Rightarrow {{d}^{2}}+{{f}^{2}}=\left( abc \right)\left( a+c \right) \\\ \end{aligned} .
Let us use b=a+c2b=\dfrac{a+c}{2} then we will have d2+f2=(ac2)(a+c)2\Rightarrow {{d}^{2}}+{{f}^{2}}=\left( \dfrac{ac}{2} \right){{\left( a+c \right)}^{2}} .
Now let us use b=a+c2b=\dfrac{a+c}{2} then we will have e2=(a+c2)2(ac)\Rightarrow {{e}^{2}}={{\left( \dfrac{a+c}{2} \right)}^{2}}\left( ac \right).
Hence we can say that 2e2=d2+f22{{e}^{2}}={{d}^{2}}+{{f}^{2}} .
Therefore we can conclude that if a,b,ca,b,c are in A.P. and geometric means of acac and abab , abab and bcbc , caca and cbcb are d,e,fd,e,f respectively then d2,e2,f2{{d}^{2}},{{e}^{2}},{{f}^{2}} are in A.P.
Hence we will mark the option “1” as correct.

Note: While answering questions of this type, we should be sure of the concepts that we are going to use in between the steps. Very few mistakes are possible in questions of this type. This is directly based on the concept of progressions without involving much calculation.