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Question

Physics Question on Units and measurement

If a, b, c and d are mass, length, time and current respectively, then b2a/c3b^2 \, a/ c^3 d has the dimensions of

A

capacitance

B

electric field

C

permittivity

D

electric potential

Answer

electric potential

Explanation

Solution

ab2c3d=[M][L2][T3][A]=[ML2T2][AT]\frac{ ab^2 }{ c^3 d } = \frac{ [ M ] [ L^2 ] }{ [ T^3 ] [ A ] } = \frac{ [ ML^2 T^{ - 2} ] }{ [ AT ] } = workcharge=\frac{ work }{ charge } = electric potential