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Question

Mathematics Question on sets

If A+B=(24\40)\begin{pmatrix} 2&-4 \\\4&0 \end{pmatrix} and 3B=(96\312)\begin{pmatrix} -9&6 \\\3&12 \end{pmatrix} then A+4B is

A

(72\112)\begin{pmatrix} -7&2 \\\1&12 \end{pmatrix}

B

(1110\712)\begin{pmatrix} 11&10 \\\7&12 \end{pmatrix}

C

(1110\712)\begin{pmatrix} -11&-10 \\\7&12 \end{pmatrix}

D

(72\712)\begin{pmatrix} -7&2 \\\7&12 \end{pmatrix}

Answer

(72\712)\begin{pmatrix} -7&2 \\\7&12 \end{pmatrix}

Explanation

Solution

The correct option is (D): (72\712)\begin{pmatrix} -7&2 \\\7&12 \end{pmatrix}