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Question: If a, b be the roots of x<sup>2</sup> + px + q = 0 and a + h, b + h are the roots of x<sup>2</sup> +...

If a, b be the roots of x2 + px + q = 0 and a + h, b + h are the roots of x2 + rx + s = 0 then-

A

pr\frac{p}{r}= qs\frac{q}{s}

B

2h = [pq+rs]\left\lbrack \frac{p}{q} + \frac{r}{s} \right\rbrack

C

p2 – 4q = r2 – 4s

D

pr2 = qs2

Answer

p2 – 4q = r2 – 4s

Explanation

Solution

a, b ® x2 + px + q = 0

a + h, b + h ® x2 + rx + s = 0

|a – b| = |(a + h) – (b + h)|

Ž D1a1\frac{\sqrt{D_{1}}}{|a_{1}|}= D2a2\frac{\sqrt{D_{2}}}{|a_{2}|}Ž p24q1\frac{p^{2}–4q}{1} = r24s1\frac{r^{2}–4s}{1}

Ž p2–4q = r2 – 4s