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Question

Mathematics Question on Quadratic Equation

If α,βα, β are the roots of a quadratic equation ax2+bx+c=0, a0ax^2+bx+c=0,\ a≠0 then α2+β2α^2+β^2

A

1b2(a2+2bc)\frac {1}{b^2}(a^2+2bc)

B

1b2(a22bc)\frac {1}{b^2}(a^2-2bc)

C

1a2(b2+2ac)\frac {1}{a^2}(b^2+2ac)

D

1a2(b22ac)\frac {1}{a^2}(b^2-2ac)

Answer

1a2(b22ac)\frac {1}{a^2}(b^2-2ac)

Explanation

Solution

The correct option is (D): 1a2(b22ac)\frac {1}{a^2}(b^2-2ac).