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Question: If A, B and C are three sets such that \(A \cap B = A \cap C\) and \(A \cup B = A \cup C\), then (...

If A, B and C are three sets such that AB=ACA \cap B = A \cap C and AB=ACA \cup B = A \cup C, then
(A). A = B
(B). A = C
(C). B = C
(D). AB=ϕA \cap B = \phi

Explanation

Solution

Before attempting this question one must have prior knowledge about the concept of sets and also remember that if AB=ACA \cup B = A \cup C which means all elements of B are in set A and set C, using this information will help you to approach the solution of the question.

Complete step-by-step answer :
According to the given information it is given that AB=ACA \cap B = A \cap C and AB=ACA \cup B = A \cup C
so, the set of B is given as; B=(AB)BB = \left( {A \cup B} \right) \cap B
since, AB=ACA \cup B = A \cup C
Therefore, B=(AC)BB = \left( {A \cup C} \right) \cap B
As we know that by the distributive property i.e. (AC)B=(AB)(BC)\left( {A \cup C} \right) \cap B = \left( {A \cap B} \right) \cup \left( {B \cap C} \right)
Therefore, B=(AB)(BC)B = \left( {A \cap B} \right) \cup \left( {B \cap C} \right)
Since, AB=ACA \cap B = A \cap C
So, B=(AC)(BC)B = \left( {A \cap C} \right) \cup \left( {B \cap C} \right)
Also, we know that by the distributive property i.e.(AB)C=(AC)(BC)\left( {A \cup B} \right) \cap C = \left( {A \cap C} \right) \cup \left( {B \cap C} \right)
Therefore, B=(AB)CB = \left( {A \cup B} \right) \cap C
Since, AB=ACA \cup B = A \cup C
Therefore, B=(AC)CB = \left( {A \cup C} \right) \cap C
Since, (AC)C=C\left( {A \cup C} \right) \cap C = C
Therefore, B=CB = C
Hence, option C is the correct option.

Note : In the above solution we used the term “set” which can be explained as an organized manner of collections of objects or elements which are represented as set-builder form or a roster form, generally the representation of sets is given as {}. In the sets numbers of elements and size are identified by the order of sets which is named as cardinality.