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Question

Mathematics Question on permutations and combinations

If a, b and c are the greatest values of 19Cp,20Cq^{19}C_{p}, \, ^{20}C_{q} and 21Cr^{21}C_{r} respectively, then :

A

a11=b22=c42\frac{a}{11} = \frac{b}{22} = \frac{c}{42}

B

a10=b11=c42\frac{a}{10} = \frac{b}{11} = \frac{c}{42}

C

a11=b22=c21\frac{a}{11} = \frac{b}{22} = \frac{c}{21}

D

a10=b11=c21\frac{a}{10} = \frac{b}{11} = \frac{c}{21}

Answer

a11=b22=c42\frac{a}{11} = \frac{b}{22} = \frac{c}{42}

Explanation

Solution

a=10C10,b=20C10a=^{10}C_{10}, b=^{20}C_{10} and c=21C10c=^{21}C_{10}
a=19C9,b=2(19C9)\Rightarrow a=^{19}C_{9}, b=2\left(^{19}C_{9}\right) and c=2111(20C10)c=\frac{21}{11}\left(^{20}C_{10}\right)
b=2a\Rightarrow b=2a and c=2111b=42a11c=\frac{21}{11}b=\frac{42a}{11}
a:b:c=a:2a:42a11=11:22:42\Rightarrow a : b : c=a : 2a : \frac{42a}{11}=11 : 22 : 42