Question
Mathematics Question on types of differential equations
If ∠A+∠B=90°, then 1+tanBtanA=
A
sec² A
B
sec² B
C
1−sin2A1
D
1+sin2A1
Answer
sec² A
Explanation
Solution
The correct option is: A and C
If ∠A+∠B=90°, then 1+tanBtanA=
sec² A
sec² B
1−sin2A1
1+sin2A1
sec² A
The correct option is: A and C